LINR 2 | Lesson 1 | Practice (Literal Equations Solutions)

  1. Solve for \(y\):  \[\begin{align}2y &= -3x+8\\\\y &= -\dfrac{3}{2}x+4\end{align}\]

  1. Solve for \(h\): \[\begin{align}A &= \dfrac{1}{2} h(b_1+b_2)\\\\2A &= h(b_1+b_2)\\\\ \ h &=\dfrac{2A}{b_1+b_2}\end{align}\]

  1. Solve for \(h\): \[\begin{align}V &= \dfrac{1}{3} πr^2h\\\\3V &= πr^2h\\\\ \dfrac{3V}{πr^2}&=h\\\\h &= \dfrac{3V}{πr^2}\end{align}\]

Return to Practice (Literal Equations).

Explore (Absolute Value)

%d bloggers like this: