- Volume = \(6\cdot10\cdot10\) or \(600\) cu in
\(SA = ph+2B\), where \(p\) is the perimeter of the base and \(B\) is the area of the base. Therefore: \(SA=40\cdot6+2(100)\) or 440 sq in.
- The tennis balls have a diameter of 2 inches.
Volume of the container: \(V = π(1)^2(6)\) or \(V ≈18.85\) cu in.
Volume of the ball: \(V = \dfrac{4π}{3}• (1)^3\) or \(V ≈4.19\) cu in
Volume of air: Volume of the container- Volume of 3 balls: \(18.85-3(4.19)\) or 6.28 cu in.
- The area of the base is \(3600\)sq ft. To find the altitude : \(\sqrt{50^2 -30^2}\) or \(40’\).
Volume: \(\dfrac{1}{3}3600\cdot40\) or \(48,000\) cu ft.
The surface area: \(\dfrac{1}{2}50\cdot60\cdot4\) or \(6000\) sq ft
