RATL 3 | Lesson 1 | Solution (Writing a Rational Expression)

One possible solution:

\(\Large\frac{x+2}{(x-7)(x+1)}\)

In order to write this expression, the denominator had to be zero if \(x\) were \( 7\) or \(-1\).  Substituting 3 for \(x\) into the denominator simplifies to \(-16\). The numerator must solve for 5 when \(x = 3\).


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