RATL 3 | Lesson 1 | Solution (Writing a Rational Expression)

One possible solution:

\(\Large\frac{x~+~2}{(x~-~7)(x~+~1)}\)

In order to write this expression, the denominator had to be zero if \(x\) were \( 7\) or \(-1\).  Substituting 3 for \(x\) into the denominator simplifies to \(-16\). The numerator must solve for 5 when \(x = 3\).


Return to (Making Connections – Writing a Rational Expression)

Go onto Lesson 2: Solving Rational Inequalities