- \(x^2+y^2+6x-4y-3 = 0\)

\(x^2+6x+y^2-4y = 3\)

\(x^2+6x+9+y^2-4y+4 = 3+9+4\)

\((x+3)^2+(y-2)^2 = 16\)

∴ center is at \((-3, 2)\) and radius is 4

- center at \((1, 4)\) and radius is 3

\((x-1)^2+(y-4)^2 = 9\)

\(x^2-2x+1+y^2-8y+16 = 9\)

\(x^2+y^2-2x-8y+8=0\)

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