# POLQ 2 | Lesson 2 | Practice 3 (Application of Completing the Square)

1).  $$x^2 + y^2 + 6x -4y – 3 = 0$$

$$x^2 + 6x + y^2 -4y = 3$$

$$x^2 +6x + 9 + y^2 -4y + 4 = 3 + 9 + 4$$

$$(x+ 3)^2 + (y – 2)^2 = 16$$

∴ center is at (-3, 2) and radius is 4

2.  center at $$1, 4)$$ and radius is 3

$$(x-1)^2 + (y – 4)^2 = 9$$

$$x^2 -2x + 1 + y^2 -8y + 16 = 9$$

$$x^2 + y^2 -2x -8y + 8=0$$