LINR 1 | Lesson 2 | Practice (Graphs of Linear Situations)

Practice

Linear Situation

A catering company charges $15.00 per guest and a flat rate of $100.00 to cater a luncheon.


Table

  1. Complete the table below to represent the cost for up to 80 guests.  Follow these steps:
  • Determine the appropriate \(x\)values needed to complete a table that represents the cost for up to 80 guests.
  • What is the starting \(x\)-value?  This value should be in the first row of the table.
  • What \(x\)value should be in the last row of the table?
  • By how much should the \(x\)-values increase from one line to the next?


Graph

2. Use the values in your table and a coordinate plane like the one shown below to graph this situation.

  • Label each axis.
  • Let the intersection of the axes represent the origin \((0,0)\).
  • Determine the scale for each axis . Be sure that the graph shows up to at least 80 guests.

 


Equation

2. Determine the slope and the \(y\)-intercept for this situation.

Slope:

\(y\)-intercept:

3. Define two variables to use in this situation.

Let _ =

Let _ =

4. Write an equation to represent the total cost to cater a luncheon for any number of guests.

 


Check solutions here.

Explore!

Go to Explore (Calculating Slope)