LINR 2|Lesson 1| Practice Absolute Value Solutions

1.  \(|2x – 7| + 3 = 8\)

\(|2x – 7| = 5\)

\(2x – 7 = 5\) or \(2x – 7 = -5\) ; \(x = 6\) or \(x = 1\)

2.  \(|3x + 2| – 2 = 12\)

\(|3x + 2| = 14\)

\(3x + 2 = 14\) or \(3x + 2 = -14\); \(x = 4\) or \(x = \frac{-16}{3}\)

3.  \(2 – |x + 3| = -7\)

\(-|x + 3| = – 9\) or \(|x + 3| = 9\) ; \(x = 6\) or \(x = -12\)

4.  \(1 – |3x -2| = 10\)

\(-|3x – 2| | = 9\) or \(|3x – 2|  = -9|\);  no solution

Go back to Absolute Value Practice

Go to Lesson 2