A Linear Situation:
- \(y=4ox+4500\); where \(y=\)elevation and \(x=\)number of hours.
- \(y = 40(8)+4500\); 4820 ft
- \(5020 = 40x + 4500\); 13 hours
Table:
- \(y=67 – 4x\); where \(x=\)hours and \(y =\)degrees
- \(y=67 – 4(2.5)\); 57 degrees
- \(37 = 67 -4x\); 7.5 hrs
Graph:
- \(y = 40 + \Large\frac{x}{4}\); \(x =\)number of chirps per min and \(y=\) temperature
- \(y = 40 + \Large\frac{300}{4}\); 115 degrees
- \(62 = 40+\Large\frac{x}{4}\); 88 chirps