GEOM 3 | Lesson 4 | Making Connections

1).  Your friend, Misha, solved the problem above by first setting up the proportion:\(\Large\frac{x}{20}= \Large\frac{5}{15}\) and found that \(x = 6\frac{2}{3}’\).  Your other friend, Jon, set up the proportion: \(\Large\frac{5}{15}=\Large\frac{x}{x+20}\) and found that \(x = 10’\).  Who is correct and why?

2).  Think of another application, create a problem around it and solve it.

Check your solutions.

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