Midsegment Theorem
The Midsegment Theorem: Segment joining the midpoints of two sides of the triangle is parallel to the third side and is \(\dfrac{1}{2}\) its length.
As a consequence to this theorem, \(ΔABC ≈ΔADC\) and \(ΔABC ≈ΔFEC\).
Is \(ΔABC ≈ΔEFD\)?
What other similarities or congruences do you find in the figure?
- In the figure above, \(BC = 10, AB = 6, AC = 8\), find \(XY, YZ\) and \( XZ\).
- \(BC = 12, YZ = 4,\) and \( AC = 10\), find \(XY, XZ \) and \(AB\).
Did you find
- \(XY = 5, YZ = 3\) and \(XZ =4\)
- \(XY = 6, XZ = 5\) and \(AB=8\)
