- \(-27x^3y^6\)
- \(\dfrac{9y^8}{x^2}\)
- \(\dfrac59\)
- \(\dfrac{x^5}2\)
- \(x^5\)
- \(\dfrac{y^2 z^2}{36}\)
- \(\Bigg(\dfrac{5}{3^2}\Bigg)^{-1}=\dfrac{9}{5}~;(-3)^{-2}=\dfrac{1}{9}~;350^0=1;~,(2^{-3}\cdot2)=\dfrac{1}{4}\); thus the order is: \(\dfrac{1}{9},\dfrac{1}{4}, 1, \dfrac{9}{5}\)