# RATL 3 | Lesson 3 | Practice (Asymptotes) Solutions

 Function Horizontal Asymptote Vertical  Asymptote $$f(x)=\dfrac{x-2}{x-3}$$ $$y= 1$$ $$x=3$$ $$f(x)=\dfrac{(x-2)(x-3)}{(x-1)(x-4)}$$ $$y= 1$$ $$x = 1$$, $$x = 4$$ $$f(x)=\dfrac{x^2+2}{x(x^2-1)}$$ $$y= 0$$ $$x = 0$$, $$x = -1$$, $$x = 1$$ $$f(x)=\dfrac{x^4}{x+1}$$ none $$x = -1$$