LINR 2 | Lesson 3 | Discuss

Let’s solve \(2x-3y<-6\) for y…

\(-3y<-2x-6\)

\(y<\Large \frac{2}{3} \normalsize x+2\)

Recall, dividing through an inequality by a negative changes the orientation of the symbol → \(y>\Large \frac{2}{3} \normalsize x+2\). (Use test points to verify!)

You can always test this out with numbers

\(2+(-4)<14\) true

\(-4<12\) still true when add -2 to each side

\(1<-3\) False. I forgot to change the orientation, I should have written

\(1>-3\) Yes!