# LINR 2 | Lesson 3 | Discuss

Let’s solve $$2x-3y<-6$$ for y…

$$-3y<-2x-6$$

$$y<\Large \frac{2}{3} \normalsize x+2$$

Recall, dividing through an inequality by a negative changes the orientation of the symbol → $$y>\Large \frac{2}{3} \normalsize x+2$$. (Use test points to verify!)

You can always test this out with numbers

$$2+(-4)<14$$ true

$$-4<12$$ still true when add -2 to each side

$$1<-3$$ False. I forgot to change the orientation, I should have written

$$1>-3$$ Yes!