# GEOM 2 | Lesson 4 | Practice Solution

1.  $$XY = 15$$

2.   $$D$$ is the midpoint of segment $$AC$$:  $$(\dfrac{5}{2},\dfrac{13}{2})$$

3.   $$7x-1 = 4x+5$$; $$x = 2$$ and $$VQ = 13$$

4.  $$7x+10 = 9x-2$$; $$x = 6$$ so $$AD = 104$$

5.  Let $$z$$ represent the altitude.

$$\dfrac{20}{z} =\dfrac{15}{z}$$; $$z^2 = 15•30$$ or $$z = 10√3$$