GEOM 2 | Lesson 4 | Practice Solution

1.  \(XY = 15\)

2.   \(D\) is the midpoint of segment \(AC\):  \((\dfrac{5}{2},\dfrac{13}{2})\)

3.   \(7x-1 = 4x+5\); \(x = 2\) and \(VQ = 13\)

4.  \(7x+10 = 9x-2\); \(x = 6\) so \(AD = 104\)

5.  Let \(z\) represent the altitude.

\(\dfrac{20}{z} =\dfrac{15}{z}\); \(z^2 = 15•30\) or \(z = 10√3\)


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